Week 2 Sapling Hw #2

Moderators: Chem_Mod, Chem_Admin

RaniyaFeroz_1E
Posts: 90
Joined: Wed Sep 30, 2020 9:32 pm

Week 2 Sapling Hw #2

Postby RaniyaFeroz_1E » Sun Jan 17, 2021 7:49 pm

The Ka of a monoprotic weak acid is 0.00214. What is the percent ionization of a 0.121 M solution of this acid?
I'm confused about how to calculate the percent ionization.

ColmConnolly3D
Posts: 90
Joined: Wed Sep 30, 2020 10:06 pm
Been upvoted: 1 time

Re: Week 2 Sapling Hw #2

Postby ColmConnolly3D » Sun Jan 17, 2021 9:06 pm

The percent ionization will be the amount of charged particles at equilibrium (for a monoprotic acid, this is just the H30+ concentration) divided by the initial concentration (in this case 0.00214M) of the acid. This will tell you what percentage of the acid has dissociated to form charged species.

Hope this helps!
Colm

Varsha Ravi 3E
Posts: 92
Joined: Wed Sep 30, 2020 9:48 pm
Been upvoted: 1 time

Re: Week 2 Sapling Hw #2

Postby Varsha Ravi 3E » Sun Jan 17, 2021 9:38 pm

Find the equilibrium value of the conjugate base at equilibrium (which would be the same as the hydronium concentration) and divide it by the initial amount of the acid that's given in the problem. Multiply that against 100 for the percentage. Hope this helps!

rhettfarmer-3H
Posts: 101
Joined: Wed Sep 30, 2020 9:59 pm

Re: Week 2 Sapling Hw #2

Postby rhettfarmer-3H » Sun Jan 17, 2021 11:53 pm

Percent Ionization =What you have made conjugate acid or base /initial base or acid *100. Therefore first you need to find all the ingredients for it. So first set up the equilibrium table and find the values. then plug them in. Hence, I look at it as a post percentage of how much was converted.

Xinying Wang_3C
Posts: 99
Joined: Wed Sep 30, 2020 9:39 pm

Re: Week 2 Sapling Hw #2

Postby Xinying Wang_3C » Mon Jan 18, 2021 4:04 pm

Basically, the percentage ionized is the [dissociated]/[original reactant]. So you would use the ICE Table to solve for the [ H+] as usual. and just use that value to calculate [H+]/0.121 M. Hope this helps.

Laura 3l
Posts: 108
Joined: Wed Sep 30, 2020 9:55 pm
Been upvoted: 1 time

Re: Week 2 Sapling Hw #2

Postby Laura 3l » Mon Jan 18, 2021 4:12 pm

Xinying Wang_3C wrote:Basically, the percentage ionized is the [dissociated]/[original reactant]. So you would use the ICE Table to solve for the [ H+] as usual. and just use that value to calculate [H+]/0.121 M. Hope this helps.


Yes you would do this and then multiply by 100 to get the percent ionization.

RaniyaFeroz_1E
Posts: 90
Joined: Wed Sep 30, 2020 9:32 pm

Re: Week 2 Sapling Hw #2

Postby RaniyaFeroz_1E » Sun Jan 24, 2021 7:04 am

Thank you so much, everyone!!

Keshav Patel 14B 2B
Posts: 94
Joined: Wed Sep 30, 2020 9:40 pm

Re: Week 2 Sapling Hw #2

Postby Keshav Patel 14B 2B » Sun Jan 24, 2021 8:06 am

Do your ice table and find the concentration of Hydroniums in the solution, after that it’s easy just multiply by 1/100.

Charlotte Chen 3B
Posts: 45
Joined: Wed Nov 18, 2020 12:29 am

Re: Week 2 Sapling Hw #2

Postby Charlotte Chen 3B » Sun Jan 24, 2021 11:24 pm

Since Ka=[H+]{A-]/[HA], you can plug in the values given so 0.00214=x^2/0.121-x , then you can solve for x using the quadratic equation and once you've solved for x, you can then divide it by the original concentration 0.121M and multiply it by 100 to get the percent ionization


Return to “Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions”

Who is online

Users browsing this forum: No registered users and 1 guest