Adding a gas
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Adding a gas
if the equation is NH4HS(s) goes to NH3(g) + H2S(g) and the Kc = 1.6*10^-4, why does adding argon gas to the equation result in no change. If a gas is not present in the reaction to begin with and then added, does it have no impact on the reaction? I thought that was only for solids and liquids.
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Re: Adding a gas
I'm not entirely sure, but I'm pretty sure Argon is an inert gas, which is why it has no impact on this chemical reaction.
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Re: Adding a gas
noble gases have no effect because they do not react with the reactants or products
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Re: Adding a gas
As others above said, adding an inert (noble) gas does not change the reaction because they do not interact with the reactants or products. Pressure of the reaction would change, but since it was not changed in response to a change in volume, the equilibrium of the reaction is not affected.
You mentioned solids and liquids, but I believe we only exclude solids and liquids from the K constant expression = [P]/[R].
You mentioned solids and liquids, but I believe we only exclude solids and liquids from the K constant expression = [P]/[R].
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Re: Adding a gas
Inert/noble gases have no effect on the equilibrium, just like how catalysts do not.
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Re: Adding a gas
Inert gases have no effect on pressure, compressing the system changes the pressure and thus K.
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Re: Adding a gas
Since Argon is a noble gas (inert gas), it is stable and therefore does not react with the reaction. Since it doesn't react with the reaction it does not make any changes, which is why it has not effect.
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Re: Adding a gas
Adding a gas doesn't have any effect because it doesn't change the concentration. When you change the pressure by changing the volume, the concentration changes thus the reaction is affected.
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Re: Adding a gas
Since argon gas is an inert gas, adding it will not have an impact on the reaction!
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Re: Adding a gas
an addition of a gas does not affect the reaction because noble gases do not react.
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Re: Adding a gas
Adding an inert gas has no effect on the concentration and therefore no effect on the reaction.
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Re: Adding a gas
It most likely has to do with concentration staying constant, that is the original gases.
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Re: Adding a gas
Your reasoning stands true! Because the noble gas is not involved in the reaction, it has no affect on the equilibrium shifts. Moreover, one could stand to reason that adding a noble gas would affect the pressure, and thus the equilibrium. This is true, but remember the volume of the chamber is not changing and the amount of P and R are staying the same, so eq. would not be affected.
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Re: Adding a gas
First, inert/noble gases do not react with the reactants nor the products. The way they affect pressure is important to note as well; there is no decrease in volume. With increased pressure as a result of decreasing volume, the concentrations of the reactants and products change (M = mol/V), causing equilibrium to shift. With noble gases, the changed pressure arises from increased moles of gas in the system, not decrease in total volume. Hope this helps! :)
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Re: Adding a gas
Thats because argon is an inert gas, which basically means that it has 0 affect on the system.
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Re: Adding a gas
Argon is an inert gas and does not react with the elements, therefore it does not affect the reaction.
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Re: Adding a gas
Hi, adding a noble gas doesn't change anything because it is an inert gas and thus doesn't react or change the concentrations of the reactants and the products.
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