Textbook problem 6.61

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claire ikemiya_2I
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Textbook problem 6.61

Postby claire ikemiya_2I » Fri Jan 29, 2021 10:31 am

Why doesn't water effect the equilibrium? I understand the addition of water doesn't have an effect on gases, but since there is an aqueous species doesn't liquid impact that?
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Nicole Huang 3F
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Re: Textbook problem 6.61

Postby Nicole Huang 3F » Fri Jan 29, 2021 10:43 am

All liquids and solids don't affect equilibrium constants! Only aqueous and gas are included in the K values because molar concentrations of solids and liquids can't change in a reaction.

Kelly Tran 1J
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Re: Textbook problem 6.61

Postby Kelly Tran 1J » Fri Jan 29, 2021 1:06 pm

In this problem water is not affecting the equilibrium because it is in its liquid state. Solids and liquids are omitted from the equilibrium constant expression, and hence do not affect the equilibrium, because the change in their concentrations are negligible.

Valerie Doan 3I
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Re: Textbook problem 6.61

Postby Valerie Doan 3I » Fri Jan 29, 2021 2:18 pm

Water or solids and liquids in general do not affect the equilibrium because their concentrations do not change by a specific amount. So, if there's a question asking "how does K change when H2O (l) is added?" the answer would be no effect. Remember only temperature can change the equilibrium constant and removing/adding products or reactants (only in aq or gas state) will change equilibrium concentrations. Pressure also plays a role in changing equilibrium concentrations and partial pressures.

ellenulitsky Dis 1I
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Re: Textbook problem 6.61

Postby ellenulitsky Dis 1I » Fri Jan 29, 2021 3:30 pm

Only gas and aqueous entities affect K. Liquids and Solids do not. Hope this helps.

Samudrala_Vaishnavi 3A
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Re: Textbook problem 6.61

Postby Samudrala_Vaishnavi 3A » Fri Jan 29, 2021 7:00 pm

If you look at the state that the water is in, it is a liquid which means it doesn't impact the equilibrium constant in any way. This is because solids and liquids aren't reactive/ no smaller chemical reactions occur within them and they are usually present in excess.

Jeffrey Hablewitz 2I
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Re: Textbook problem 6.61

Postby Jeffrey Hablewitz 2I » Fri Feb 05, 2021 6:27 pm

If the glucose solution was sufficiently concentrated, adding water would cause the equilibrium to shift right, as it would decrease the concentration of glucose (a product). However, in this reaction, the glucose solution is so dilute that changing the volume of solvent would not appreciably change the concentration of glucose.

Kaihan_Danesh_2J
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Re: Textbook problem 6.61

Postby Kaihan_Danesh_2J » Mon Feb 08, 2021 5:12 am

No, water does not affect that because it is a solvent, it is what makes those compounds aqueous. As in, the compounds are aqueous because they are in the water. Being a solvent, any change in H2O concentration is negligible and not the focus of these exercises.


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