Quadratic Formula
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Re: Quadratic Formula
You use it to solve for X, which you then plug back into the reactants and/or product(s) concentration equations to find the final concentration after equilibrium is re-established.
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Re: Quadratic Formula
When using the ICE table you will either adding or subtracting x based on the concentration. If it has a given concentration or you were able to solve it subtract x from it, if the concentration is unknown just put x. Remember to look at the coefficients for the balanced reaction since it will be deciding if the x is 2x,3x,4x.... Once you have the concentration with the xs subtracting from them, you can put the product over the reactants equal to the given K. You will then cross multiply and from there you can apply the quadratic formula. Remember any negative values from the quadratic formula are not valid.
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Re: Quadratic Formula
The quadratic formula is applied after using the ICE table and plugging in your values to solve for K. In order to simplify for the missing X value, you need to use quadratic formula to solve.
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Re: Quadratic Formula
you use the quadratic formula to solve for x after you have done your ice table.
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Re: Quadratic Formula
If you are ever solving an equation algebraically and you reach a point where you have simplified it to a "variable squared" plus "the same variable" plus an integer, it may seem as though you cannot solve for the variable, but this is when you would plug the coefficients to the variables as well as the integer into the quadratic formula to solve for the unknown variable.
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Re: Quadratic Formula
After you have completed the ice table, and it seems that there is x^2 in the final equation, then you would plug in the coefficients for each term into the quadratic formula to solve for x as one of the concentrations.
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Re: Quadratic Formula
You use the quadratic formula to solve for the variable x from the ICE box. You are usually given a value K and set up the products over reactants equal to K. Then, you work through algebra to isolate or factor x. You will most likely be left with a quadratic equation equal to 0. That is when you apply the quadratic formula to find x, which will be plugged back into the ICE box to find the molar compositions of your equation.
Re: Quadratic Formula
You use the quadratic formula to solve for "X" from your ice table. X usually ends up being a variable you used to substitute in for an unknown amount of change. Once you fill out the table, you need to solve for X to get the final concentrations/bars of the products and reactants and equilibrium.
Re: Quadratic Formula
Hi,
The quadratic formula looks a little scary but is actually not. When you write an equation you can typically use algebra to get the equation into the "ax^2 + bx + c = 0" form. You then simply insert this "a," "b," and "c" into the quadratic formula.
The quadratic formula looks a little scary but is actually not. When you write an equation you can typically use algebra to get the equation into the "ax^2 + bx + c = 0" form. You then simply insert this "a," "b," and "c" into the quadratic formula.
Re: Quadratic Formula
We use the quadratic formula after using the ice table! It is used to solve for X and once we get that, we plug it back to the equation to find the end concentration.
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Re: Quadratic Formula
Yes, you may need to use the quadratic formula when solving for equilibrium. You may find it useful when using ICE tables. If you are solving for an x quantity and were not provided with any of the equilibrium concentrations of your products or reactants you will probably have x values in both your products and reactants and need to use the quadratic equation to solve for that unknown quantity.
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Re: Quadratic Formula
Hey! The quadratic formula is used to solve for X after you finish setting up your ICE table based on the balanced equation and concentration equation. You use this to solve for potential values of K.
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Re: Quadratic Formula
After completion of an ICE table, the written-out expression of the equilibrium constant would contain Xs. The quadratic formula would be used to solve for the Xs.
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Re: Quadratic Formula
You use quadratic formula to solve for the value of x. Once you find the x value, you plug it back into the equation to find the final concentration.
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Re: Quadratic Formula
The quadratic formula is used to find the x value. You will usually get a negative and positive x, but you only use the positive x and plug the x value back into the equation to find the concentration of the reactants and products.
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Re: Quadratic Formula
After you have completed the ICE table, you would use the quadratic formula to solve for x.
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Re: Quadratic Formula
Hi!
You would first set up the ICE table to set up your equations to solve for the missing x, relative to the stoichiometry of the reaction. After setting up these equations, you would set them equal to your K to solve for x. In other words, you are working with the K = products/reactants equation, and substituting your product and reactant equilibrium concentrations for the equations that you wrote out in the ICE table. After this, you would solve the equation to have a quadratic equation (a^2 + bx + c = 0) and then solve for x in this equation using the quadratic formula. After finding your x value, plug it back in to your original equations written out in the ICE table to find your final concentrations.
You would first set up the ICE table to set up your equations to solve for the missing x, relative to the stoichiometry of the reaction. After setting up these equations, you would set them equal to your K to solve for x. In other words, you are working with the K = products/reactants equation, and substituting your product and reactant equilibrium concentrations for the equations that you wrote out in the ICE table. After this, you would solve the equation to have a quadratic equation (a^2 + bx + c = 0) and then solve for x in this equation using the quadratic formula. After finding your x value, plug it back in to your original equations written out in the ICE table to find your final concentrations.
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Re: Quadratic Formula
After completing the ICE table, it should give you your set up and everything you need to set up your quadratic equation which you'll solve for x.
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Re: Quadratic Formula
If I have a fraction containing two either addition or subtraction equations that both contain an x value, for example 0.5 = (0.2+x) / (0.8-x), how do I solve for x?
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Re: Quadratic Formula
When solving for equilibrium, it is useful to set up an ICE table, using the stoichiometric coefficients to determine whether a compound gained/lost an x. Next set the equilibrium equations, which should include x's, of the reactants and products (R/P) equal to the equilibrium constant, K. After manipulating the equation, a quadratic should result. Lastly, solve for x and use the value to determine the new concentrations of each compound.
Re: Quadratic Formula
You use the quadratic formula after constructing your ICE table and determine the equilibrium of a certain component of the chemical reaction or to determine the K value. The change row of the ICE table tells you whether you will be adding or subtracting nX amount. Then this is added to a numerical value to create an expression that will be expanded to then be plugged into the quadratic formula.
Re: Quadratic Formula
u use the quadratic formula to solve for x to find the concentration of hydrogen ions if the question gives Ka or find the concentration of hydroxide ions if the question gives Kb
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Re: Quadratic Formula
You use the quadratic formula when you solve for x using the ICE table, when you plug in your values with x into the K formula ([P]/[R]).
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Re: Quadratic Formula
After you set up your ICE table, set up your equilibrium constant equation (products/reactants) = K. Usually the value of K will be given and so you just have to solve for x with the quadratic equation as previously explained. However, be sure to check the value of K to see if it's possible to approximate (is it < 10^-3?). If it fits the aforementioned criteria, then we can remove the x in the denominator and you'll be left with a situation in which you solve for x by taking the square root of both sides without having to go through the trouble of using the quadratic formula. Hope this helps.
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Re: Quadratic Formula
When solving for equilibrium, you use the ICE table method. By using this method, you should have the concentrations of the different molecules for the equilibrium portion. Then you use the equation to solve for the equilibrium constant (K=[Products]/[Reactants]) using these new concentrations. Normally, you will be given the proper K value to use and you can plug the numbers in. Given K = x^2/([reactants]-x) and from here you continue to solve for x. You would use the quadratic formula once you have the x^2+x-c=0 formula to solve for the value of x. x can only be a positive value so you should only get one answer!
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Re: Quadratic Formula
After your ICE table, you use the quadratic equation when K>10^-3. If K<10^-3 then you can omit the -x and just use alegrbra to solve for x.
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Re: Quadratic Formula
Just by using the formula and plug numbers in, but I was also wondering if we are allowed to install programs on our graphing calculator to solve some problems that require the quadratic formula faster?
Re: Quadratic Formula
All you must do is use it to solve for x. Usually, that gives you two x values (because it is a quadratic equation), and you pick which ever value makes sense in regards to the problem, usually the positive x value.
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Re: Quadratic Formula
You use an ICE table (Initial Concentration, Change in concentration, and equilibrium concentration) to make an equation solving for Ka. Using the Ka equation (product)(product)/(reactant)(reactant). Usually, this looks like Ka = X^2/Initial - X. Then solve for X. If Ka is 10^-4 or less, you can take away the X in the initial - x and don't have to use a quadratic equation.
Re: Quadratic Formula
After completing the ice table you set K equal to the equilibrium concentrations of products over reactants from the ice table using the variable x and you use the quadratic formula to find the value of x. You can then plug the value of X in to get the exact equilibrium concentrations.
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