K, Kw, PKa, PKb, pH, pOH

[emmavandal1K]

How are K, Kw, PKa, PKb, pH, pOH all related to each other?

[Aarush_Maddela_3A]

K is the equilibrium constant. This value gives us an understanding of the amount of product and reactant present in the reaction at equilibrium. Kw is the equilibrium constant of the auto ionization of water. A very small concentration of pure water at 25 degrees Celsius will always dissociate to H30+ and OH-. The concentration of these values determines kw which is 10^-14 at 25 degrees Celsius. Whenever you see P in front of a value, it means to take the -log of. In this case, pKa means to take the negative log of Ka. The same applies to pKb. For pH and pOH, you would take the negative log of the hydronium ion concentration for pH and the negative log of the hydroxide ion concentration for pOH. Hope this helps!

[MelodyJiang]

K is the equilibrium constant you calculate using ([C]^c[D]^d)/([A]^a[B]^b), while Kw is the equilibrium constant for water (1.0x10^-14 for 25 degrees celsius). pKa + pKb = pKw (which is 14). pH + pOH = 14 as well because this is synonymous with pKa +pKb = pKw. Lastly, Ka x Kb = Kw. With these relationships, you can convert from one to another.

[Skylar Smith 1E]

They are all related to each other because if you have the value for one you can find the other values. K is the chemical equilibrium constant. KA is the chemical equilibrium constant for acids and KB is for bases. These two multiplied gives Kw which equals 1x10^-14. Furthermore, Pka plus Pkb equal pkw which is 14. Additionally, to find the pH, you -log (H30+) which you can find from the using an ICE table. Then to find the pOH the equation is pH minus pOH equals 14.