12.7

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RenuChepuru1L
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Joined: Thu Jul 27, 2017 3:00 am

12.7

Postby RenuChepuru1L » Thu Dec 07, 2017 11:57 pm

Hey! Can someone help me figure out how to draw the conjugate base, also is naming oxoacids in the fundamental J?

Shannon Wasley 2J
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Re: 12.7

Postby Shannon Wasley 2J » Fri Dec 08, 2017 12:25 am

Conjugate bases is the compound remaining after an acid has donated a proton (H+). Therefore in reference to this problem, the conjugate base would be drawn by removing the one H atom, which is the H+ proton that the acid donates. The conjugate base of the given acid would just be without the Hydrogen atom. This can also be illustrated by the fact that if the given acid was HNO2, the conjugate base would be without the one H proton, making it NO2.
Regarding the oxoacids, I could not find much information about them in fundamental J, however I was able to find some information in chapter 12.10 and in fundamental D.

Minie 1G
Posts: 63
Joined: Fri Sep 29, 2017 7:04 am

Re: 12.7

Postby Minie 1G » Fri Dec 08, 2017 12:29 am

For part a, the conjugate base to HClO3 is ClO3-. The lewis structure has a central Cl atom, connected to two oxygen atoms with double bonds and a third oxygen with a single bond. The double bonded oxygens have 2 lone pairs each while the single bond connected oxygen has 3 lone pairs (6 total lone electrons). Finally, there is one lone pair of electrons on the central Cl atom. Resonance applies here. It can break the octet rule because it's in the 3rd period.

Part b the conjugate base of HNO2 is NO2-. This has nitrogen as the central atom connected to two oxygens via a double bond to one and a single bond to the other. It shows resonance cause the double bond can be to any of the oxygens. One oxygen has 3 lone pairs, the other has 2, and nitrogen has 1.


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