Neutralization Reaction (Textbook Exercise J.9B)

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Sasha Gladkikh 2A
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Neutralization Reaction (Textbook Exercise J.9B)

Postby Sasha Gladkikh 2A » Sun Nov 28, 2021 7:16 pm

Textbook Exercise J.9 states:

"Identify the salt that is produced from the acid–base neutralization reaction between (a) potassium hydroxide and acetic acid, CH3COOH; (b) ammonia and phosphoric acid; (c) calcium hydroxide and bromous acid; (d) sodium hydroxide and hydrosulfuric acid, H2S (both H atoms react). Write the complete ionic equation for each reaction."

For part B, the answer is:

3NH3(aq) + 3H+ + PO43-(aq) → 3NH4+(aq) + PO43-(aq)

The acid and base involved in this neutralization reaction are H3PO4 and NH3, which are both weak. In the answer key, why does the weak acid H3PO4 dissociate? In the textbook, it states that when writing the neutralization of a weak acid or a weak base, the formula for the molecular form of the weak acid or base is used, because intact acid molecules are the dominant species in solution.

Also, why is H2O(l) not included in the complete ionic equation?

Jonathan Sautter 1J
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Re: Neutralization Reaction (Textbook Exercise J.9B)

Postby Jonathan Sautter 1J » Fri Dec 03, 2021 11:26 am

The reason for this is that acids donate protons while bases accept protons. Due to this, NH3 is going to accept the 3 H+ ions from PO4 and create (NH4)3PO4. The reason that water is not formed in this reaction is because water is only formed in a neutralization reaction when a strong base is present. If the base is not strong, then water will not be created.


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