Amphoteric Oxide Aluminum Oxide

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Alex Nguyen 3I
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Joined: Fri Sep 25, 2015 3:00 am

Amphoteric Oxide Aluminum Oxide

Postby Alex Nguyen 3I » Thu Nov 26, 2015 12:10 pm

Can someone explain to me how the reaction between sodium hydroxide, sodium hydroxide, and water works?
I know that aluminum oxide is acting as an acidic oxide here. It's reacting with a base, so shouldn't salt and a water form? Does this have anything to do with the water being involved as a reactant?

Chem_Mod
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Re: Amphoteric Oxide Aluminum Oxide

Postby Chem_Mod » Thu Nov 26, 2015 9:56 pm

Above equation doesn't seem to be balanced in hydrogen or oxygen.

I believe the right side is 2NaAlO2 + H2O so that a salt and water is formed.

Alex Nguyen 3I
Posts: 100
Joined: Fri Sep 25, 2015 3:00 am

Re: Amphoteric Oxide Aluminum Oxide

Postby Alex Nguyen 3I » Fri Nov 27, 2015 2:20 pm

I actually wrote the equation down wrong. It's , which is balanced, but I'm not sure if the transition metal complex is a salt or not.

Aashi_Patel_3B
Posts: 20
Joined: Wed Sep 21, 2016 2:57 pm

Re: Amphoteric Oxide Aluminum Oxide

Postby Aashi_Patel_3B » Sat Nov 19, 2016 4:15 pm

Alumnium oxide splits and the oxygen accepts a proton which then forms water. Aluminium oxide is an acid because it reacts with a base to form a salt and water which happens during a neutralization reaction...someone correct me if I'm wrong?

-Aashi Patel 4E


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