Homework problem 12.23

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404757006
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Joined: Wed Sep 21, 2016 3:00 pm

Homework problem 12.23

Postby 404757006 » Thu Dec 01, 2016 10:35 pm

Does anyone have an easy explanation for problem 12.23?

Christine_Mavilian_3E
Posts: 30
Joined: Fri Jul 22, 2016 3:00 am

Re: Homework problem 12.23

Postby Christine_Mavilian_3E » Thu Dec 01, 2016 11:48 pm

Kw is equal to the concentration of your hydronium ion times the concentration of your hydroxide ion. In other words Kw = Ka times Kb. In the problem you've been give the value of your Kw which is 2.1x10^-14. Set this value equal to Ka and Kb (where 2.1x10^-14=Ka x Kb) and substitute those for x values so you would get x^2= 2.1x10^-14.Take the square root and you will get your x value ( the concentration) for both your hydronium and hydroxide ions which in this case would be the same value. The concentration is your molarity and if you take the -log of your concentration, you will get your pH value. Here is the formula : pH=-log [(concentration)].

I hope this helps!


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