12.29

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Cam Bear 2F
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Joined: Thu Jul 27, 2017 3:01 am

12.29

Postby Cam Bear 2F » Tue Dec 05, 2017 8:02 pm

Hi guys! I'm a little confused on chapter 12 number 29 letter c "Calculate the pH and pOH for 0.0092M of Ba(OH)2(aq)." Why did they multiply the concentration by 2? How do you know it produces 2 hydroxide ions? Thanks!

Jasmine Wu 1L
Posts: 55
Joined: Thu Jul 27, 2017 3:00 am
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Re: 12.29

Postby Jasmine Wu 1L » Tue Dec 05, 2017 9:22 pm

I think you would multiply by 2 because, in the formula Ba(OH)2, there are 2 moles of OH- (look at the subscript) for 1 mole of Ba(OH)2. So, there's a 2:1 ratio.

Ya Gao
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am
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Re: 12.29

Postby Ya Gao » Tue Dec 05, 2017 9:23 pm

Hey, there are two hydroxide ion per Ba(OH)2 because if we write out the balanced equation: Ba(OH)2----Ba2+ + 2OH-, for every Ba(OH)2 molecule ionized, two hydroxide ions is produced. That's why you need to multiply it by 2. Hope it helps.


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