Problem J.9

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Rita Chen 1B
Posts: 112
Joined: Sat Jul 20, 2019 12:15 am

Problem J.9

Postby Rita Chen 1B » Mon Dec 02, 2019 9:08 pm

Identify the salt that is produced from the acid-base neutralization reaction between potassium hydroxide and acetic acid.

How would I do this? I know it is supposed to produce water but the salt doesn't look quite right if I have more than 1 carbon

Nawal Dandachi 1G
Posts: 102
Joined: Sat Sep 28, 2019 12:16 am

Re: Problem J.9

Postby Nawal Dandachi 1G » Mon Dec 02, 2019 9:44 pm

it would produce water and potassium acetate.
CH3COOH + K(OH) → H2O + CH3COOK

Nare Nazaryan 1F
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

Re: Problem J.9

Postby Nare Nazaryan 1F » Mon Dec 02, 2019 10:24 pm

Potassium acetate is produced:

CH3CO2H(aq)+K^+(aq)+OH^-(aq)-->K^+(aq)+CH3CO2^-(aq)+H2O(l)

Chantel_2I
Posts: 109
Joined: Sat Sep 07, 2019 12:19 am

Re: Problem J.9

Postby Chantel_2I » Wed Dec 04, 2019 10:31 am

How would you do it for ammonia and phosphoric acid?

Ashley Tran 2I
Posts: 108
Joined: Thu Jul 11, 2019 12:17 am

Re: Problem J.9

Postby Ashley Tran 2I » Wed Dec 04, 2019 10:39 am

Chantel_4B wrote:How would you do it for ammonia and phosphoric acid?


We knew the ionic compound created would be ammonium phosphate. Since ammonium is +1 and phosphate is 3- we need three NH4+ to balance out the PO4 3- From there, work backwards to write the reactants side of the chemical reaction.

3NH3(aq) + H3PO4(aq) --> 3NH4+(aq) + PO4 3-(aq)


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