HW 6.B #9

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HW 6.B #9

Postby 605379296 » Thu Dec 05, 2019 1:11 am

I thought for this problem you had to plug in 1.5 into -log(HA) to find the pOH,, but I'm not sure if that's right... How would I approach this problem?

Indy Bui 1l
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Joined: Sat Sep 07, 2019 12:19 am

Re: HW 6.B #9

Postby Indy Bui 1l » Thu Dec 05, 2019 3:36 pm

pH=-Log[Hydronium ion concentration]
pOH=-Log[Hydroxide concentration]

pH+pOH=14, so

You can convert all of these into pH and then rank them.

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