HW 6.B #9

Moderators: Chem_Mod, Chem_Admin

605379296
Posts: 58
Joined: Sat Aug 17, 2019 12:16 am

HW 6.B #9

Postby 605379296 » Thu Dec 05, 2019 1:11 am

I thought for this problem you had to plug in 1.5 into -log(HA) to find the pOH,, but I'm not sure if that's right... How would I approach this problem?

Indy Bui 1l
Posts: 99
Joined: Sat Sep 07, 2019 12:19 am

Re: HW 6.B #9

Postby Indy Bui 1l » Thu Dec 05, 2019 3:36 pm

pH=-Log[Hydronium ion concentration]
pOH=-Log[Hydroxide concentration]

pH+pOH=14, so
14-pOH=pH

You can convert all of these into pH and then rank them.


Return to “Lewis Acids & Bases”

Who is online

Users browsing this forum: No registered users and 1 guest