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Postby AngieGarcia_4F » Sat Dec 07, 2019 3:58 pm

On question 6.21 in the textbook why can't the Oxygen on the Thymine accept protons?

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Re: 6.21

Postby nicolely2F » Sat Dec 07, 2019 5:24 pm

It already has two bonds (1 double bond), therefore its octet is complete and its formal charge is zero. It's the most stable situation possible for Oxygen

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Re: 6.21

Postby Petrina Kan 2I » Sat Dec 07, 2019 6:51 pm

I am also confused about this. I know the formal charge of Oxygen is 0 so we wouldn't want to change it, but wouldn't the nitrogen accepting a proton also change its formal charge to make it not 0?

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