Focus 6 exercise 6.5

[Anna Castaneda 2E]

Hydrogen peroxide, H2O2, reacts with sulfur trioxide to form peroxomonosulfuric acid, H2SO5, in a Lewis acid–base reaction. (a) Write the chemical equation for the reaction. (b) Draw the Lewis structures of the reactants and product (in the product, one —OH group in sulfuric acid is replaced by an —OOH group). (c) Identify the Lewis acid and Lewis base.

I'm not sure why the acid is SO3 and the base is H2SO5. Could someone explain how they got this answer?

[Trisha Mantri 3L]

The Lewis acid will be the one that accepts the electron pair and the Lewis base will be the one that donates the electron pair. Thus, based on how the lewis structure of the final product actually looks, we can tell that SO3 was the one that accepted the electrons from H2SO5 to form the compound. I'm not sure that is the best answer, but the back of the book might make more sense.