J.7 textbook

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405745446
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Joined: Fri Sep 24, 2021 5:37 am

J.7 textbook

Postby 405745446 » Sat Dec 04, 2021 8:38 pm

Hi, the question reads:
Select an acid and a base for a neutralization reaction that results in the formation of: (d) potassium phosphate.
Can someone walk me through their reasoning on how they reached their answer? I've managed to get through a-c but am stuck on this last part.

Lawrence Javelo Disc 3B
Posts: 77
Joined: Fri Sep 24, 2021 6:43 am

Re: J.7 textbook

Postby Lawrence Javelo Disc 3B » Sat Dec 04, 2021 8:44 pm

So because this is a neutralization reaction, we know that a strong base and a strong acid are the reactants of this reaction. So because we have potassium phosphate, K3PO4, we can begin to build our reaction:

We have 3K+'s and 1 PO4 3-.

We know a strong acid with PO4 is H3PO4.
We know a strong base has OH in it so we can get KOH

Now we build our equation:
3KOH + H3PO4 --> K3PO4 +3H2O

Hope this helps!


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