Hi!
I am having a bit of trouble with part d and e of that question. Can someone explain how you would go about writing the equilibria for those parts?
Textbook 6.A.4
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Steve Chung 2E
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Re: Textbook 6.A.4
For part d, it would be HPO4 2- (aq) + H2O (l) <=> OH - (aq) + H2PO4 - because you are going from a base to form its conjugate acid.
For part e (not 100% sure about this one) is CO(NH2)2 (aq) + H2O (l) <=> OH - (aq) + CONH2NH3 + because the proton is being transferred from the water to urea.
For part e (not 100% sure about this one) is CO(NH2)2 (aq) + H2O (l) <=> OH - (aq) + CONH2NH3 + because the proton is being transferred from the water to urea.
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