Question 12.9b

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Anmol Dhaliwal 2C
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Joined: Wed Sep 21, 2016 2:57 pm

Question 12.9b

Postby Anmol Dhaliwal 2C » Mon Nov 21, 2016 9:12 pm

For question 12.9b it asks which reactions can be classified as reactions between Bronsted acids and bases and to identify the acid and base for the ones that can. part b has the equation NH4I (s) ----> NH3 (g)+ HI (g) and in the solutions manual it lists NH4+ as the acid and I- as the base. Can someone please explain why this would be? Why is this possible if HI does not have a nitrogen in it but can still be the base and NH4 the acid? Thanks!

Marco_Romo_1M
Posts: 36
Joined: Wed Sep 21, 2016 2:59 pm

Re: Question 12.9b

Postby Marco_Romo_1M » Mon Nov 21, 2016 10:08 pm

NH4I is the same as NH4+ and I-. Therefore, the NH4+ is the acid because it donates a proton to I- to form HI and I- is a base because it accepts the proton from NH4+. In the process, NH4+ becomes NH3 (ammonia). Hope this helps.


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