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12.27

Posted: Sat Jun 09, 2018 8:28 pm
by huntercrespo1C
Wants to prepare 200.0 mL of a 0.025 M HCl solution but uses a 250.0 mL flask
I understand part a but where does the equation pH = -log * (200mL * .025M)/250.0M come from for part b

Re: 12.27

Posted: Sun Jun 10, 2018 11:29 am
by Jack Martinyan 1L
M1V1=M2V2

(0.025)(200)=(M2)(250)

M2= (0.025)(200)/250

M2 is the concentration of the H30+

pH=-log[H3O+]

pH=-log[(0.025)(200)/250]