7th edition 6A.9 Part C

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Brice McKeown 3D
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Joined: Fri Sep 28, 2018 12:25 am

7th edition 6A.9 Part C

Postby Brice McKeown 3D » Fri Dec 07, 2018 1:03 am

So the equation is CH3COOH+ NH3----> CH3CONH2+ H2O and the question is can this be classified as a reaction between a bronsted acid and base. The hint is to write the net ionic equation which I understand... but the answer key says that there is no proton transferred. I am just confused how no proton is transferred if there are hydrogen ions in places that they were not before.

405161024
Posts: 36
Joined: Fri Sep 28, 2018 12:25 am

Re: 7th edition 6A.9 Part C

Postby 405161024 » Fri Dec 07, 2018 7:20 pm

I think it's because for it to be considered a proton transfer it really has to be just the proton that changes places and in this case it's rather NH that is substituting the oxygen (which then bonds with the H2 produced)


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