J11 Question

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J11 Question

Postby GraceChen2A » Tue Nov 25, 2014 5:19 pm

The question for J11 asks to write the chemical equation for the proton transfer reaction of the given cation/anion with water, provided that the anion/cation is a weak acid/base. The compounds given are NaC6H5O, KClO, C5H5NHCl, and NH4Br. The equation for the first question was NaC6H5O+H2O --> NaC6H5OH + OH-, while the equation for the second question was ClO+H2O -> HClO +OH-. What I don't understand is when to separate the cation from the rest of the compound. In the second equation, potassium was taken out of the equation while in the first question, sodium was kept. In the 3rd and 4th equations, Cl and Br, respectively, were also taken out of the equation.

Astred 1D
Posts: 15
Joined: Fri Sep 26, 2014 2:02 pm

Re: J11 Question

Postby Astred 1D » Mon Dec 01, 2014 4:23 pm


I don't have an exact answer to your question. However, in the back of the book the answer to the first equation does not include Na. We are asked to look at the reaction of the cation or anion that is a weak acid or base. So because C6H5O^- is a weak acid and Na actually forms a strong base (NaOH) we look at the proton transfer reaction of C6H5O^- .

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