7th edition 6A.9 a and c

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Katherine Fitzgerald 1A
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7th edition 6A.9 a and c

Postby Katherine Fitzgerald 1A » Sun Jul 28, 2019 10:51 am

In 6A.9, we are asked to identify the acid and base in the following chemical equations:

(a) NH4I (aq) + H20 (l) --> NH3 (aq) + H30+ (aq) +I- (aq)

(c) CH3COOH (aq) + NH3 (aq) --> CH3CONH2 (aq) + H20 (l)


In part a, why do we say that NH4+ is the acid, rather than Nh4I?

In part c, there is no acid or base according to the manual (no proton is transferred). However, it seems like NH3 has lost a proton and combined with Oh to form H20. In what sense is a proton not being transferred?

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Re: 7th edition 6A.9 a and c

Postby Chem_Mod » Sun Jul 28, 2019 2:09 pm

The Iodine does not participate in any of the transfer of the proton, only the part of NH4+ to NH3. The iodine only serves to make it a salt so it can be easily added to the water solution, it serves a spectator role.


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