Correct equation for 6A.3?

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DesireBrown1J
Posts: 98
Joined: Wed Sep 18, 2019 12:18 am

Correct equation for 6A.3?

Postby DesireBrown1J » Sun Dec 01, 2019 9:02 pm

I got the correct answers for all the parts in 6A.3, yet I wanted to double check to make sure my chemical equations for the proton transfer equilibria were correct because that wasn't in the solutions manual.

a) H2SO4 + H2O <-> H3O+ + HSO4-
b) C6H5NH3+ + H2O <-> H3O+ + C6H5NH2
c) H2PO4- + H2O <-> H3O+ + HPO42-
d) HCOOH + H2O <-> H3O+ + HCOO-
e) NH2NH3+ + H2O <-> H3O+ + NH2NH2

Michael Du 1E
Posts: 117
Joined: Sun Sep 22, 2019 12:16 am

Re: Correct equation for 6A.3?

Postby Michael Du 1E » Sun Dec 01, 2019 9:05 pm

Yes! I got the same equations as you

Anna Chen 1K
Posts: 104
Joined: Thu Jul 25, 2019 12:18 am

Re: Correct equation for 6A.3?

Postby Anna Chen 1K » Sun Dec 01, 2019 9:06 pm

I also got the same equations!

KaleenaJezycki_1I
Posts: 127
Joined: Sat Aug 17, 2019 12:18 am
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Re: Correct equation for 6A.3?

Postby KaleenaJezycki_1I » Wed Dec 04, 2019 9:12 pm

DesireBrown3K wrote:I got the correct answers for all the parts in 6A.3, yet I wanted to double check to make sure my chemical equations for the proton transfer equilibria were correct because that wasn't in the solutions manual.

a) H2SO4 + H2O <-> H3O+ + HSO4-
b) C6H5NH3+ + H2O <-> H3O+ + C6H5NH2
c) H2PO4- + H2O <-> H3O+ + HPO42-
d) HCOOH + H2O <-> H3O+ + HCOO-
e) NH2NH3+ + H2O <-> H3O+ + NH2NH2



So in part a would the H2SO4 be the acid and the H2SO4- be the conjugate base?

DesireBrown1J
Posts: 98
Joined: Wed Sep 18, 2019 12:18 am

Re: Correct equation for 6A.3?

Postby DesireBrown1J » Thu Dec 05, 2019 12:42 pm

KaleenaJezycki_4G wrote:
DesireBrown3K wrote:I got the correct answers for all the parts in 6A.3, yet I wanted to double check to make sure my chemical equations for the proton transfer equilibria were correct because that wasn't in the solutions manual.

a) H2SO4 + H2O <-> H3O+ + HSO4-
b) C6H5NH3+ + H2O <-> H3O+ + C6H5NH2
c) H2PO4- + H2O <-> H3O+ + HPO42-
d) HCOOH + H2O <-> H3O+ + HCOO-
e) NH2NH3+ + H2O <-> H3O+ + NH2NH2



So in part a would the H2SO4 be the acid and the H2SO4- be the conjugate base?



H2SO4 would be the acid and HSO4- would be the base.


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