Question J.9 in the textbook says "Identify the salt that is produced from the acid–base neutralization reaction between (a) potassium hydroxide and acetic acid,
(b) ammonia and phosphoric acid; (c) calcium hydroxide and bromous acid; (d) sodium hydroxide and hydrosulfuric acid,
(both atoms react). Write the complete ionic equation for each reaction."
could someone explain how to get the products for (b) and (c)? It doesn't seem obvious to me that NH4+ and PO43- are left as ions and Br binds to O2.
Textbook J.9
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Re: Textbook J.9
Postby Ethan Famas 1H » Sun Dec 05, 2021 9:32 pm
With these problems, it could be a little difficult to visualize how the reaction progresses. This is my thought process:
b) We have ammonia (NH3, which is a base) and phosphoric acid (H3PO4). Ammonia is a molecule and so it doesn't dissociate into ions the way H3PO4, an Arrhenius acid, does. H3PO4 dissociates into 3H+ and PO43-. Because NH3 is a base, it can accept H+ from the H3PO4, creating ammonium ion NH4+. Therefore, our product salt would be the combination of the NH4+ and the PO43-. (We would need three of the NH4+ to neutralize the 3- charge of the PO43-, so that's why the salt is (NH4)3PO4.)
c) We have calcium hydroxide Ca(OH)2, and bromous acid (HBrO2). Both can dissociate into ions. The -OH from Ca(OH)2 and the H+ from HBrO2 form water, and the ions Ca2+ and BrO2- form the salt, Ca(BrO2)2. (We need two of the BrO2- to neutralize the Ca2+.)
b) We have ammonia (NH3, which is a base) and phosphoric acid (H3PO4). Ammonia is a molecule and so it doesn't dissociate into ions the way H3PO4, an Arrhenius acid, does. H3PO4 dissociates into 3H+ and PO43-. Because NH3 is a base, it can accept H+ from the H3PO4, creating ammonium ion NH4+. Therefore, our product salt would be the combination of the NH4+ and the PO43-. (We would need three of the NH4+ to neutralize the 3- charge of the PO43-, so that's why the salt is (NH4)3PO4.)
c) We have calcium hydroxide Ca(OH)2, and bromous acid (HBrO2). Both can dissociate into ions. The -OH from Ca(OH)2 and the H+ from HBrO2 form water, and the ions Ca2+ and BrO2- form the salt, Ca(BrO2)2. (We need two of the BrO2- to neutralize the Ca2+.)
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