Dissociation
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Patrick Wilson 2B
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- Joined: Wed Sep 21, 2016 3:00 pm
Dissociation
In class Dr. Lavelle talks about how much CH3COO (-) dissociates as a product when CH3COOH reacts with water. How do we calculate this dissociation value??
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Hung_Sabrina_3N
- Posts: 22
- Joined: Fri Jul 22, 2016 3:00 am
Re: Dissociation
CH3COOH + H2O -> CH3COO- + H3O+
Is the equation for this dissociation. The Ka value will either be given or you have to find it.
You can find the amount of the product that is dissociated using the Ka value that would be given in this case it is 1.8× 10–5 M. You will use [CH3COO-][H3O+]/[CH3COOH]=Ka and use the initial molarity of CH3COOH to calculate for [CH3COO-][H3O+].
If you need to find Ka the concentrations of the reaction at equilibrium should be given then you just use [CH3COO-][H3O+]/[CH3COOH] to find Ka.
Is the equation for this dissociation. The Ka value will either be given or you have to find it.
You can find the amount of the product that is dissociated using the Ka value that would be given in this case it is 1.8× 10–5 M. You will use [CH3COO-][H3O+]/[CH3COOH]=Ka and use the initial molarity of CH3COOH to calculate for [CH3COO-][H3O+].
If you need to find Ka the concentrations of the reaction at equilibrium should be given then you just use [CH3COO-][H3O+]/[CH3COOH] to find Ka.
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