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12.1

Posted: Sun Jul 30, 2017 11:37 pm
by Jacinda Wollenweber 1D
I am a bit confused about writing the formulas of conjugate bases, in terms of what happens to hydrogen. In part d) we are given HCO3-, but then when we write the conjugate the hydrogen disappears. Is it because it is being added to the other side, causing the charge to change to 2-?

Re: 12.1

Posted: Sun Jul 30, 2017 11:40 pm
by Jacinda Wollenweber 1D
Also, in part f) CH3COOH, does the O2 in the answer represent the two O at. the end of the compound after hydrogen is removed? I hope my question makes sense lol

Re: 12.1

Posted: Sun Jul 30, 2017 11:42 pm
by 504754253
can someone explain the conjugate base.. is it just another way of saying weak? serious question

Re: 12.1

Posted: Tue Dec 05, 2017 8:29 pm
by Liam Maxwell 2E
I am confused about part b. It is asking for the conjugate acid of NH2NH2. Both nitrogens have a lone pair, so could the hydrogen from H2O attach to either one?

Re: 12.1

Posted: Wed Dec 06, 2017 11:53 pm
by Jana Sun 1I
Liam Maxwell 3F wrote:I am confused about part b. It is asking for the conjugate acid of NH2NH2. Both nitrogens have a lone pair, so could the hydrogen from H2O attach to either one?


Yes, you're right. The hydrogen could form on either nitrogen. NH2NH2 will only accept one hydrogen to create a conjugate acid and I'm not sure if it matters which nitrogen it attaches to.