J.15 6th Edition

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Karolina herrera1F
Posts: 33
Joined: Sat Feb 02, 2019 12:15 am

J.15 6th Edition

Postby Karolina herrera1F » Wed Jul 24, 2019 6:13 pm

I’m stuck on how to find the chemical equation for the proton transfer reaction of this cation or anion with water: (a) NaC6H5O; (b) KClO; (c) C5H5NHCl; (d) NH4Br. Can someone please explain how to do find a chemical equation exactly maybe even just part a ? Do we always add H2O to it ? As a reactant ?

Jennifer Zhou 1A
Posts: 31
Joined: Mon Jun 17, 2019 7:23 am

Re: J.15 6th Edition

Postby Jennifer Zhou 1A » Wed Jul 24, 2019 8:04 pm

so NaC6H5O dissociate into cation Na+ and C6H5O-, then the Na+ forms NaOH with the OH- from water and C6H5O- from C6H6O with H+ from water. NaC6H5O + H2O = NaOH + C6H6O

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