6A.9

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Kelvin Chung 1C
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Joined: Sat Aug 24, 2019 12:15 am

6A.9

Postby Kelvin Chung 1C » Mon Dec 02, 2019 9:54 pm

I know this question doesn't ask for a conjugate acid or base, but I was just curious what they would be in this chemical reaction.

6A.9 c) NH4I(am) + KNH2(am) --> KI(am) + 2NH3(l)
"am" indicates that liquid ammonia is the solvent

The textbook's use of --> makes it seem like this reaction isn't reversible. Is that why there isn't a clear conjugate acid/base in this reaction?

A Raab 1K
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Joined: Sat Aug 24, 2019 12:16 am

Re: 6A.9

Postby A Raab 1K » Mon Dec 02, 2019 10:00 pm

NH4I is a salt, so there isn't a conjugate acid or base. You can find which acids or bases it is derived from though, which is NH4+ and I -

Kelvin Chung 1C
Posts: 50
Joined: Sat Aug 24, 2019 12:15 am

Re: 6A.9

Postby Kelvin Chung 1C » Mon Dec 02, 2019 10:28 pm

A Raab 1K wrote:NH4I is a salt, so there isn't a conjugate acid or base. You can find which acids or bases it is derived from though, which is NH4+ and I -


If you look at the other parts of the same question, there are salts, but the conjugate acid and base are easily identifiable.

In part a) NH4I(aq) + H2O(l) --> NH3(aq) + H3O+(aq) + I-(aq) :
the conjugate acid should be H3O+ and the conjugate base NH3. Is that right, or does this reaction not have any conjugate acid/base either?


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