6A.9

[Kelvin Chung 1C]

I know this question doesn't ask for a conjugate acid or base, but I was just curious what they would be in this chemical reaction.

6A.9 c) NH₄I_(am) + KNH_2(am) --> KI_(am) + 2NH_3(l)
"am" indicates that liquid ammonia is the solvent

The textbook's use of --> makes it seem like this reaction isn't reversible. Is that why there isn't a clear conjugate acid/base in this reaction?

[A Raab 1K]

NH4I is a salt, so there isn't a conjugate acid or base. You can find which acids or bases it is derived from though, which is NH4+ and I -

[Kelvin Chung 1C]

NH4I is a salt, so there isn't a conjugate acid or base. You can find which acids or bases it is derived from though, which is NH4+ and I -

If you look at the other parts of the same question, there are salts, but the conjugate acid and base are easily identifiable.

In part a) NH₄I_(aq) + H₂O_(l) --> NH_3(aq) + H₃O⁺_(aq) + I^-_(aq) :
the conjugate acid should be H₃O⁺ and the conjugate base NH₃. Is that right, or does this reaction not have any conjugate acid/base either?