Conjugate Base

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curry 1E
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Joined: Wed Sep 18, 2019 12:15 am

Conjugate Base

Postby curry 1E » Tue Dec 03, 2019 6:04 pm

How would you make CH3COOH a conjugate base? I know you have to remove a H+ but do you remove it from the H3 or the H at the end?

Camellia Liu 1J
Posts: 51
Joined: Sat Aug 24, 2019 12:15 am

Re: Conjugate Base

Postby Camellia Liu 1J » Tue Dec 03, 2019 6:07 pm

I think that you would remove the H at the end. The conjugate base of acetic acid is CH3COO-.

nickianel_4b
Posts: 50
Joined: Thu Jul 25, 2019 12:17 am

Re: Conjugate Base

Postby nickianel_4b » Thu Dec 05, 2019 6:03 pm

^^I know that it becomes CH3COO- just from practice, but can someone remind me again why it donates the H+ at the end and not one of the H+ ions attached to the C?

Michelle N - 2C
Posts: 117
Joined: Wed Sep 18, 2019 12:19 am

Re: Conjugate Base

Postby Michelle N - 2C » Fri Dec 06, 2019 9:18 am

nickianel_4b wrote:^^I know that it becomes CH3COO- just from practice, but can someone remind me again why it donates the H+ at the end and not one of the H+ ions attached to the C?


I think that's because they usually lose H+ at the more electronegative atom first, and oxygen is more electronegative than carbon.

Shutong Hou_1F
Posts: 117
Joined: Sat Sep 14, 2019 12:17 am

Re: Conjugate Base

Postby Shutong Hou_1F » Fri Dec 06, 2019 10:06 am

nickianel_4b wrote:^^I know that it becomes CH3COO- just from practice, but can someone remind me again why it donates the H+ at the end and not one of the H+ ions attached to the C?

-COOH, or carboxyl group, is the organic acidic group, so when losing a proton, the proton would come from the carboxyl group.


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