Fundamentals J.9

[simona_krasnegor_1C]

Hi everyone! Could someone explain their thought process for answering a-d on 9 of fundamentals J? Thanks!

[Anthony_3C]

So I've typed the equations. The general rule here is to for cations and anions in each acid and base, then put the cations and adios together. That forms the salt. Don't forget to watch out for oxidation numbers (charge) of each ion. Also another product is H2O but I didn't add it since its obvious.

[Rachel Fox - 3F]

For this problem, first we want to figure out the salt that is going to be formed, and then we want to write out the ionic equation using this information. Ionic compounds will be split up into cations and anions since they are aqueous and water will be a liquid.

For part A, CH3COOH gives up the H+ because it is the acid and the OH from KOH accepts the proton. The salt that forms if KCH3COO, potassium acetate.

For part B, NH3 is the base because it will accept the proton from H3PO4 to form NH4+. The salt is (NH4)3PO4, ammonium phosphate.

For part C, Ca(BrO2)2, calcium bromite, is the salt because the H from BrO2 reacts with the OH from CaOH to form water.

For part D, the salt is Na2S, sodium sulfide, because the OH and the H participate in the neutralization reaction to form water and the Na2S is the salt.

From this information, we can then write our ionic equation with the acid and base on one side and the salt and water (if it is present) on the other side.