6A.3 part c

Moderators: Chem_Mod, Chem_Admin

Kaethe Zappacosta 2L
Posts: 106
Joined: Fri Sep 24, 2021 7:29 am

6A.3 part c

Postby Kaethe Zappacosta 2L » Mon Nov 29, 2021 8:56 pm

Write the chemical equations for the proton transfer equilibria of the following acids in aqueous solution and identify the conjugate acid–base pairs in each case: H2PO4-

The answer is that H2PO4- is an acid and it becomes HPO4^2-, but why isn't it a base to become H3PO4?

505766240
Posts: 100
Joined: Fri Sep 24, 2021 7:08 am

Re: 6A.3 part c

Postby 505766240 » Tue Nov 30, 2021 11:52 am

Since H2PO4- is the acid, it will be the one to donate an H+ to H2O, making it H3O+. If H2PO4- is an acid, it's not going to accept another H+ as it's a proton donor.

Andrew Nguyen 1E
Posts: 101
Joined: Fri Sep 24, 2021 6:34 am
Been upvoted: 1 time

Re: 6A.3 part c

Postby Andrew Nguyen 1E » Tue Nov 30, 2021 12:09 pm

Hi,
H2PO4 - is an amphoteric compound since it can either accept a proton to become H3PO4 (and thus act as a base) or it can lose a proton to become HPO4 2- (and thus act as an acid). The textbook just only shows the reaction in which H2PO4 - acts as an acid.


Return to “Conjugate Acids & Bases”

Who is online

Users browsing this forum: No registered users and 6 guests