Achieve #13
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Achieve #13
For these types of questions, am I to focus on the pH and pKa that is given? Is that all I really need to know to determine the answer in this question?
Re: Achieve #13
Yes, I think you only need to know the pH and pKa in order to solve this equation. I think to put it simply, in comparing the pH and pKa, you'll see that the pH is greater in number than the pKa, and therefore more basic (since Ka is a number used to find what side of the reaction a is being tended towards, it is basically measuring what the goal pH? of the reaction is, sorry it's hard for me to explain this part but it's not that important). Anyways, since the pH at hand is more basic, and tending towards the right side of the equation (where the products are charged). Hope this helped!
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Re: Achieve #13
From what I understand is if the pH is > than the the pKa for an acid, then it will end up charged.
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Re: Achieve #13
All you need to focus on is whether or not the pH is greater than or less than the pKa. If the pH is less than the pKa, in terms of acids, then the predominant species is neutral and if the pH is greater than the pKa, then the predominant species is charged.
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Re: Achieve #13
For this question you just need to keep these 2 rules in mind:
1) when pH > pKa, the acid is negatively charged
2) when pH < pKa, the acid is neutral
1) when pH > pKa, the acid is negatively charged
2) when pH < pKa, the acid is neutral
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Re: Achieve #13
Aida Fraser 2I wrote:can someone explain what pKa is theoretically?
I am also unsure of what pKa exactly is.
Re: Achieve #13
Kiana Rogers 1D wrote:Aida Fraser 2I wrote:can someone explain what pKa is theoretically?
I am also unsure of what pKa exactly is.
pKa is the -log of the Ka value. Ka is the acid dissociation constant that can be calculated from the equation Ka = [H+][A-]/[HA]
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Re: Achieve #13
From what I understand you only have to focus on the pH and pKa. If the pH is larger than the pKa the acid is charged. Ka is the acid dissociation and pKa is the log of Ka.
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