Equilibrium for Kw
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Equilibrium for Kw
Under which exact conditions does 10^-14 = (10^-7)(10^-7) apply for water? I was under the impression that this is under only complete equilibrium and pH7.
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Re: Equilibrium for Kw
Kw is the autoprotolysis constant of water at 25 degrees celsius and is used in a reaction where water forms [H3O+] or [OH-]. If we have [H3O+] we can use Kw=1x10^-14 to find [OH-] and vice versa. I hope this helps!
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Re: Equilibrium for Kw
For Kw related problems, they should give you the specific Kw value at whatever specific temperature they provide in the question, even if it's not at 25 degrees celsius!
Regardless of the Kw value given, [H3O+] and [OH-] is always going to be equal to each other, and you can find the value for both by taking the square root of the the Kw value you're given. Hopefully this makes sense!
Regardless of the Kw value given, [H3O+] and [OH-] is always going to be equal to each other, and you can find the value for both by taking the square root of the the Kw value you're given. Hopefully this makes sense!
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