question 12.63

Acidity
Basicity
The Conjugate Seesaw

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Blake_Katsev_2E
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Joined: Wed Sep 21, 2016 2:57 pm

question 12.63

Postby Blake_Katsev_2E » Tue Nov 22, 2016 1:06 pm

why when finding the Ka would the denominator be (1-.024) x .110 rather than being .11-.00264 which the ice box indicates that it should be.

Chem_Mod
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Re: question 12.63

Postby Chem_Mod » Wed Nov 23, 2016 9:54 am

In this problem, x is 0.024*0.110 and since the eq [C6H5COOH] is 0.110-x, one can factor out the 0.110 and get 0.110*(1-0.024) this is the same as writing 0.110-(0.024*0.110)

Maya_McNealis1B
Posts: 9
Joined: Wed Sep 21, 2016 2:59 pm

Re: question 12.63

Postby Maya_McNealis1B » Tue Nov 29, 2016 9:49 pm

Another question regarding problem 63:

What is the significance of the line in the student solutions manual referencing octylamine? How does that relate to the calculation of Ka?


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