## question 12.63

Acidity $K_{a}$
Basicity $K_{b}$
The Conjugate Seesaw $K_{a}\times K_{b}=K_{w}$

Blake_Katsev_2E
Posts: 113
Joined: Wed Sep 21, 2016 2:57 pm

### question 12.63

why when finding the Ka would the denominator be (1-.024) x .110 rather than being .11-.00264 which the ice box indicates that it should be.

Chem_Mod
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Joined: Thu Aug 04, 2011 1:53 pm
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### Re: question 12.63

In this problem, x is 0.024*0.110 and since the eq [C6H5COOH] is 0.110-x, one can factor out the 0.110 and get 0.110*(1-0.024) this is the same as writing 0.110-(0.024*0.110)

Maya_McNealis1B
Posts: 9
Joined: Wed Sep 21, 2016 2:59 pm

### Re: question 12.63

Another question regarding problem 63:

What is the significance of the line in the student solutions manual referencing octylamine? How does that relate to the calculation of Ka?

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