Can you classify acids as strong or weak from their formulas alone? [ENDORSED]
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Can you classify acids as strong or weak from their formulas alone?
Can you classify acids as strong or weak from their formulas alone?
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Re: Can you classify acids as strong or weak from their formulas alone?
No, usually not. The only strong acids are the ones that are listed as "strong acids," and we know this because a Ka value doesn't exist-- everything dissociates so [HA] == 0, and Ka becomes undefined.
Theoretically, you could deduce based on electronegativity its ionic vs covalent character. But just memorize the strong acids.
Theoretically, you could deduce based on electronegativity its ionic vs covalent character. But just memorize the strong acids.
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Re: Can you classify acids as strong or weak from their formulas alone?
I'm not entirely sure, but for the purpose of this class, memorize the list of strong acids. All other acids will most likely be weak acids, according to my PLF.
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Re: Can you classify acids as strong or weak from their formulas alone?
Does anybody know if the list of strong acids in the course reader is exhaustive?
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Re: Can you classify acids as strong or weak from their formulas alone?
Better to memorize the list of all strong acids and bases. I would assume that if an acid or base is not strong, then it is weak.
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Re: Can you classify acids as strong or weak from their formulas alone?
So does that mean for any acid or base that has a K value, we can disregard the subtracted "x" from the reactants when setting up the equilibrium formula?
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Re: Can you classify acids as strong or weak from their formulas alone?
Yes, I think you are correct in assuming that because the x value would be so small anyways that it doesn't matter if you subtract it. However it is important to remember that it is still greater than 0 because if it was 0 then your numerator wouldn't make sense either.
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Re: Can you classify acids as strong or weak from their formulas alone? [ENDORSED]
divya_devineni_1E wrote:So does that mean for any acid or base that has a K value, we can disregard the subtracted "x" from the reactants when setting up the equilibrium formula?
Only for K values that are less than 10-4 as I discussed in class.
Remember to check the % product formed and if it is less than 5% of the initial reactant concentration then approximation is acceptable.
If one has an acid or base with a K = 10-1 (for example) then X is unlikely to be less than 5%.
K will not be given for a strong acid and base. Look for this in a question if you don't recognize the acid or base as strong/weak.
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