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Question 12.27

Posted: Sat Dec 03, 2016 10:07 am
by Dan_Jin_1K
Hey everyone!

Can someone offer me an explanation on how to do this problem?

A careless laboratory technician wants to prepare 200.0 mL of a 0.025 m HCl(aq) solution, but uses a 250.0-mL volumetric ask by mistake. (a) What would the pH of the desired solution have been? (b) What will be the actual pH of the solution as prepared?

Thanks!

Re: Question 12.27

Posted: Sat Dec 03, 2016 12:34 pm
by Emily Wang 1H
We can find the number of moles of HCl given what the concentration and volume should have been. However the technician put it in a different volume, which would change the molarity. Now, we can find the pH of both since we can find out the concentration of both.