12.55 Part A

Acidity
Basicity
The Conjugate Seesaw

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604744616
Posts: 34
Joined: Sun Jun 25, 2017 3:00 am

12.55 Part A

Postby 604744616 » Tue Aug 01, 2017 11:26 am

I am having trouble finding or figuring out the value for the CH^3CO^2- which is the value we need to plug-in in order to find the value of
[H^3O+]? I can post a picture of what I mean, I just know you need to plug in the values to find H^3o+ but I have every other values except that one?

Sarah_Wilen
Posts: 62
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Re: 12.55 Part A

Postby Sarah_Wilen » Tue Aug 01, 2017 2:01 pm

I wrote the dissociation equilibrium equation for CH3COOH, then drew an ICE table for it. I looked up the Ka online and plugged it into the dissociation constant equations. Next, I solved for x and found the value for [H3O+]. Using the now known [H3O+] value, I was able to calculate the pH and pOH.

Yizhou Liu 3L
Posts: 19
Joined: Fri Sep 29, 2017 7:07 am

Re: 12.55 Part A

Postby Yizhou Liu 3L » Sun Dec 03, 2017 3:25 pm

I think you are talking about the Ka value for Ch3COOH. Those numbers are called acidity constants at 25 c, which are given on page 477 table 12.1.


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