## 12.55 Part A

Acidity $K_{a}$
Basicity $K_{b}$
The Conjugate Seesaw $K_{a}\times K_{b}=K_{w}$

604744616
Posts: 34
Joined: Sun Jun 25, 2017 3:00 am

### 12.55 Part A

I am having trouble finding or figuring out the value for the CH^3CO^2- which is the value we need to plug-in in order to find the value of
[H^3O+]? I can post a picture of what I mean, I just know you need to plug in the values to find H^3o+ but I have every other values except that one?

Sarah_Wilen
Posts: 62
Joined: Fri Jun 23, 2017 11:39 am
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### Re: 12.55 Part A

I wrote the dissociation equilibrium equation for CH3COOH, then drew an ICE table for it. I looked up the Ka online and plugged it into the dissociation constant equations. Next, I solved for x and found the value for [H3O+]. Using the now known [H3O+] value, I was able to calculate the pH and pOH.

Yizhou Liu 3L
Posts: 19
Joined: Fri Sep 29, 2017 7:07 am

### Re: 12.55 Part A

I think you are talking about the Ka value for Ch3COOH. Those numbers are called acidity constants at 25 c, which are given on page 477 table 12.1.