12.45  [ENDORSED]

The Conjugate Seesaw

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Kayla Ikemiya 1E
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Postby Kayla Ikemiya 1E » Sun Dec 03, 2017 11:08 pm

So the back of the book has two different ways of arriving at the fact that 2,4,6 trichlorophenol. Is it enough to just look at which compound has a greater Ka value or do we need to know that the chlorine atoms have a greater withdrawing power?

Hannah Chew 2A
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Re: 12.45  [ENDORSED]

Postby Hannah Chew 2A » Mon Dec 04, 2017 12:30 pm

I'm assuming you are referring to 12.43 instead of 12.45, but I would use the "withdrawing power" or electronegativity differences to explain why 2,4,6 trichlorophenol has a larger Ka. You would use the Ka to identify which is stronger, but to "account for the difference in acid strength," you would have to look at the structure itself.

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Re: 12.45

Postby Humza_Khan_2J » Mon Dec 04, 2017 2:30 pm

If the attached atoms to an O-H bond have a higher electronegativity, they delocalize the charge on the O- and make it more stable. If anion of an acid post-ionization is more stable, then it will be more acidic because this molecular with ionize more than others, simply due to the anion being more stable than other anions.

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