## What is kA value?

Acidity $K_{a}$
Basicity $K_{b}$
The Conjugate Seesaw $K_{a}\times K_{b}=K_{w}$

Amina Durrani 3G
Posts: 52
Joined: Sat Jul 20, 2019 12:16 am

### What is kA value?

What exactly does kA mean? I know its the equilibrium value, but when you calculate it, do you say that it is the amount of acid dissociated?

AVerma_F19
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### Re: What is kA value?

It basically gives you the ratio between the (product of the concentration of each of the products)/(product of the concentration of each of the reactants). Using this, you can calculate the concentration of the reactants or products using the kA given.

TarynD_1I
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

### Re: What is kA value?

kA is the acid dissociation constant, and larger values for kA means that the acid is stronger and dissociates better, while smaller values for kA means that the acid is weaker and does not dissociate as well.

Nathan Nakaguchi 1G
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### Re: What is kA value?

kA is the ionization constant which lets you know how ionized/dissociated a solution is. The more ionized the stronger it is, the less ionized the weaker.

Aarushi Solanki 4F
Posts: 107
Joined: Sat Jul 20, 2019 12:17 am

### Re: What is kA value?

The value of kA is the acid disassociation constant for a reaction at equilibrium. Essentially, this means that kA is the ratio of concentration of products (multiplied) to concentration of reactants (multiplied) when these values are in the equilibrium state.

MKearney_4G
Posts: 50
Joined: Fri Aug 30, 2019 12:18 am

### Re: What is kA value?

k is calculated by [concentration of products multiplied together]/[concentration of reactants multiplied together] when the solution is at equilibrium. When the M of products is really high compared to the M of reactants, that means the reaction is carried out to near completion. For dissociation of acids, kA measures how much the acid dissociates and thus how strong it will be.

Strong acids do not generally have a written kA for these problems because it would be so insanely large that it's practically useless: just assume 100% dissociation.