The Conjugate Seesaw

Moderators: Chem_Mod, Chem_Admin

Nikita Patra 3J
Posts: 50
Joined: Sat Jul 20, 2019 12:16 am


Postby Nikita Patra 3J » Sun Dec 01, 2019 2:53 pm

How do you calculate Kb? Is it the recipricol of Ka?

Aarushi Solanki 4F
Posts: 107
Joined: Sat Jul 20, 2019 12:17 am

Re: Kb

Postby Aarushi Solanki 4F » Sun Dec 01, 2019 3:20 pm

Kb is the base dissociation constant, so the higher the value is, the stronger the base is. Kb multiplied by Ka should give Kw, the dissociation constant for water (at equilibrium). So, Kb = Kw/Ka.

Posts: 102
Joined: Thu Jul 25, 2019 12:17 am

Re: Kb

Postby 405268063 » Sun Dec 01, 2019 4:53 pm

Just like for Ka, Kb is calculated by this equation: [B+][OH-]/[BOH]. A lower Kb value indicates a stronger base.

Return to “Acidity & Basicity Constants and The Conjugate Seesaw”

Who is online

Users browsing this forum: No registered users and 1 guest