Value of Kw question

Acidity
Basicity
The Conjugate Seesaw

Moderators: Chem_Mod, Chem_Admin

JohnArthurReyes_1B
Posts: 18
Joined: Fri Sep 25, 2015 3:00 am

Value of Kw question

Postby JohnArthurReyes_1B » Mon Nov 30, 2015 6:18 pm

The value of Kw for water at body temperature (37°C) is 2.1 X 10^-14. (a)What is the molarity of H3O+ ions and the pH of neutral water at 37°C? (b) What is the molarity of OH- in neutral water at 37"C?

For part a, I understand that Kw=[H3O] [OH-]
and were given Kw so 2.1 x 10^-14=[H30] [OH-]. I don't know where to go from here with these two pieces of information.

For part b, I understand if I get [H3O] solving for [OH] would entail dividing Kw/[H3O]

Franca Park 3J
Posts: 64
Joined: Fri Sep 25, 2015 3:00 am

Re: Value of Kw question

Postby Franca Park 3J » Mon Nov 30, 2015 8:06 pm

In water we assume that the concentration of [H3O+] = [OH-]
(such as when Kw = 1.0 x 10^-14, [H3O+] = 1.0 x 10^-7 and [OH-] = 1.0 x 10^-7)
so Kw = 2.1 x 10^-14 = [H3O+][OH-]
but since [H3O+] = [OH-]
Kw = 2.1 x 10^-14 = x^2
so x = square root 2.1 x 10^-14
Then, you get the pH by taking the -log of x.

Part b is simple since you already assumed [H3O+] = [OH-].
[OH-] = x

Kai_Chiu 1F
Posts: 19
Joined: Fri Sep 29, 2017 7:03 am

Re: Value of Kw question

Postby Kai_Chiu 1F » Thu Dec 07, 2017 2:15 pm

Franca Park 3J wrote:In water we assume that the concentration of [H3O+] = [OH-]
(such as when Kw = 1.0 x 10^-14, [H3O+] = 1.0 x 10^-7 and [OH-] = 1.0 x 10^-7)
so Kw = 2.1 x 10^-14 = [H3O+][OH-]
but since [H3O+] = [OH-]
Kw = 2.1 x 10^-14 = x^2
so x = square root 2.1 x 10^-14
Then, you get the pH by taking the -log of x.

Part b is simple since you already assumed [H3O+] = [OH-].
[OH-] = x


[H3O+] = [OH-] is simply because it is water? Or is it because the question stated neutral water?

Zoe FC 1C
Posts: 43
Joined: Wed Nov 18, 2020 12:18 am

Re: Value of Kw question

Postby Zoe FC 1C » Wed Jan 20, 2021 12:05 am

This is an old thread but I'm wondering the same thing– how do we know that H30=OH?

Namita Shyam 3G
Posts: 62
Joined: Tue Nov 17, 2020 12:20 am

Re: Value of Kw question

Postby Namita Shyam 3G » Sat Jan 23, 2021 6:34 pm

I'm also wondering why they would be equal...any help would be appreciated.

Lizbeth Garcia 1F
Posts: 102
Joined: Wed Sep 30, 2020 9:39 pm

Re: Value of Kw question

Postby Lizbeth Garcia 1F » Sat Jan 23, 2021 7:24 pm

They would be equal because the problem claims the water is neutral. When water is neutral [H30+]=[OH-].

Katie Nye 2F
Posts: 100
Joined: Wed Sep 30, 2020 9:55 pm

Re: Value of Kw question

Postby Katie Nye 2F » Sat Jan 23, 2021 7:30 pm

Kai_Chiu 1F wrote:
Franca Park 3J wrote:In water we assume that the concentration of [H3O+] = [OH-]
(such as when Kw = 1.0 x 10^-14, [H3O+] = 1.0 x 10^-7 and [OH-] = 1.0 x 10^-7)
so Kw = 2.1 x 10^-14 = [H3O+][OH-]
but since [H3O+] = [OH-]
Kw = 2.1 x 10^-14 = x^2
so x = square root 2.1 x 10^-14
Then, you get the pH by taking the -log of x.

Part b is simple since you already assumed [H3O+] = [OH-].
[OH-] = x


[H3O+] = [OH-] is simply because it is water? Or is it because the question stated neutral water?


Water is always neutral unless it says otherwise so those would be the same!

Carla Bruebach 1C
Posts: 100
Joined: Fri Sep 24, 2021 5:54 am

Re: Value of Kw question

Postby Carla Bruebach 1C » Mon Jan 31, 2022 12:48 pm

Since water is neutral its concentration of H3O+ and OH- are equal.

105764441
Posts: 47
Joined: Mon Jan 09, 2023 8:30 am

Re: Value of Kw question

Postby 105764441 » Wed Jan 25, 2023 7:00 pm

Kw is the ionization constant of water. Ionization means the gain or loss of an electron from a molecule. In the case of water, the molecules that are losing electrons are H3O+ and OH-, and they are losing/gaining an electron in the form of a hydrogen ion. Water is a neutral substance. On the PH scale from 0 which is the most acidic, to 14, which is alkaline or basic, it measures at a 7 and thus is neutral. What does this mean? This means that the hydroxide and hydronium ions are essentially equal in concentration in water. So, if we are given the ionization constant, all we must do is take the square root of the value for the constant, which will tell us the concentration of each molecule! I hope this helps!


Return to “Acidity & Basicity Constants and The Conjugate Seesaw”

Who is online

Users browsing this forum: No registered users and 3 guests