pH to [H+]

[Ellen Tsai 3D]

I don't remember the formula to go from pH to [H+]. or pOH respectively, thanks!

[Jack Amos 2I]

The formula is:

[Gabby Burgess 2I]

Here are all the formulas I have for switching from pOH to pH, hopefully they help.

pH=-log[H3O+]
[H3O+]=10^(-pH)
pOH=-log[OH-]
[OH-]=10^(-pOH)
pH+pOH=14
[H+]=10^(-pH)

[Gianna Sciole 2F]

pH = -log[H+]
because of this, we can also say that:
[H+] = 10^-pH
we also know that:
pOH = -log[OH-] (because [H+]*[OH-]=10^-14).
so we can say that:
[OH-] = 10^-pOH
however if you want it using pH, since we know that pH + pOH =14, it would be: [OH-] = 10^-(14-pH)

[Diego Gonzalez 1H]

In order to get from pH to [H+] you would do 10^(-pH).

[Isabelle Kludt 2B]

[H+] = 10^-pH

[Ameen Shaheen 2I]

H+ Concentration = 10^-pH

[Michael 1G]

The way to calculate the concentration of Hydrogen ion in solution when given the pH is to take 10 and raise it to the -pH power. Ex: if the pH of a solution is 1 the [H+] would be 10^-1=0.1M.

[Emily Hou 1H]

[H+] = 10^-pH
pOH= 14-pH

[Sean Sanders 1E]

To go from pH to [H+] you just need to work backwards. Because we know the formula for pH = -log[H+], we can rearrange the terms to solve for [H+] which gives us [H+]= 10^(-pH)

[Iman Gauhar 3E]

Hi! Here are the formulas for converting from the different values:
-log[H3O+] = pH
-log[OH-] = pOH
pH + pOH = 14
[pH][pOH] = 10^-14

[Joshua Lee 3C]

To find [H+] from the pH equation, you must simply undo the pH equation. pH=-log[H+]. In other words, to rearrange the equation to get [H+], you would undo the base 10 logarithm and get 10^-pH=[H+]. You can do this same process to find [OH-] from the pOH equation.

[Matthew Nguyen 3G]

You can find [H+] by using the formula [H+] 10^-pH.

[Nicole Ton 3C]

To go from pH to [H+], we do pH=-log[H+]. To go from pH to pOH, we do pOH=14-pH

[Lindsey Walter 3E]

To go from pH to [H+], use this formula: [H+] = 10^(-pH).

[Bela Patel 2B]

To go from pH to [H+], you would do 1*10^-pH and to go from [H+] to pH, you would do -log([H+]).

[daniellediem1k]

[H+] = 10 ^(-pH)

[HaleyC 2F]

To go from pH to [H+] you do 10^pH.

[madeleinewright]

To get the pH from [H+], you take 10^-pH.

[Julia Todorov 2F]

to get from pH to [H+] you do 10^-pH value! and for pOH you would do 10^-OH

[Eszter Kovacs 1A]

You can calculate concentration of H+ from pH by 10^(-pH).

[Hannah Thornton 1F]

The formulas to go back and forth from pH to [H+] are: [H+]=10^(-pH) and pH=-log[H+].

[Hana Aflatooni]

[H+]= 10^-pH

[Samantha Toscano 2C]

Use [H+] = 10^-pH.
Use [OH-] = 10^-pOH. To find pOH -> pOH = 14 - pH

[Coraly De Leon]

Hi, it is: [H+]= 10^-pH

[Anisa Morales 1L]

The formula is [H+]=10^-PH

[Madelyn_Rios_2c]

pH=-log[H+]
pOH= -log[OH+] or (14-pH)

[Lizzy Bulla 3K]

The formula is as follows:

[H+] = 10^-pH

[Omar Alami 3H]

Hi,

The formula is . I find this graphic helpful when trying to remember and figure out which conversions to use depending on the context.

[amreen_sandhu1k]

[H+]=10^(-pH) !

[Chris Korban 1D]

the best way to do it is to just do [H+]=10^-ph

[Sally_Luo_3F]

it would be [H+]=10^-ph

for example, if ph is 3 then the value for H+= 10^-3

[Omeed Kalan]

Its just -log[H+]=pH
and 10^-pH

[Maddie Klee 3K]

Hi! To go from pH to [H+], you simply use the equation: 10^-pH.

[Sophia Hartwell 1F]

The formula is [H] = 10^-pH. With that being said, to find [OH], the formula is [OH] = 10^-pOH. Hope this helps!

[Mahli Martinez 2I]

To convert pH to [H+], use the formula pH= 10^-pH. Some scientific calculators actually show this as the inverse calculation!

[AndreyCastellanos 3H]

pH = -log[H+]
&
[H+] = 10^-pH

[Gabby Burgess 2I]

To pH to [H+], you want to use the formula 10^-pH=[H+]. It also works for the [OH-] to pOH conversion as well.

[Shannon Clark 1F]

to go from pH to [H+] the equation is:

[H+] = 10^-pH

similarly, to convert from pOH to [OH-]:

[OH-] = 10^-pOH

[505468108]

pH = -log([H30+])
[H3O+] = 10^-pH

[Audrey2B]

Anything with a p in front of it means take the -log. PH is the -log of the concentration of hydronium ions.