Textbook 6A.23

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Jose-Joaquin Garcia 1K
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Joined: Mon Nov 13, 2023 8:29 am

Textbook 6A.23

Postby Jose-Joaquin Garcia 1K » Wed Jan 31, 2024 4:05 pm

Hey so I found the concentration of Barium ions that agrees with the textbook by just dividing the moles by the volume of the container. How would I go about solving for the concentrations of hydroxide and hydronium though? I’m not exactly sure if I need to make a balanced equation with H2O as a solvent or not. Any guidance is greatly appreciated.

Freddy_Gold 3A
Posts: 83
Joined: Fri Sep 29, 2023 11:09 am

Re: Textbook 6A.23

Postby Freddy_Gold 3A » Wed Jan 31, 2024 4:11 pm

For this, since Ba(OH)2 is a strong base, it would fully dissociate. It is important to remember here that there are 2 OH- for every one Ba(OH)2, so the concentration of OH- is twice that of Ba(OH)2. Then, using [H3O+]x[OH-]=1x10-14, we can find the concentration of H3O+, and then take the -log([H3O+]) to get pH.


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