12.55 (d)

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Lena Nguyen 2H
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12.55 (d)

Postby Lena Nguyen 2H » Tue Dec 05, 2017 12:02 pm

I didn't understand the solutions manual explanation for HCOOH and its electron withdrawal ability for part d on 12.55. Can someone explain it?


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Re: 12.55 (d)

Postby Chem_Mod » Tue Dec 05, 2017 1:16 pm

Hi, Lena,
The strength of an acid depends on the presence of electron-withdrawing or -donating groups. Methyl (CH3) in acetic acid is electron donating group, that will push electrons towards O-H bond, thus making the acids weaker (and the bond stronger). Formic acid doesn't have a methyl group and therefore will be stronger (due to the absence of any electron-donating groups).

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