12.29C

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Connie2I
Posts: 29
Joined: Fri Sep 29, 2017 7:07 am

12.29C

Postby Connie2I » Thu Dec 07, 2017 12:33 am

For problems such as 12.29C, why do we multiply Ba(OH)2 by 2 to get the concentration of OH? Is it because of the 2 outside the parentheses?

AnuPanneerselvam1H
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am

Re: 12.29C

Postby AnuPanneerselvam1H » Thu Dec 07, 2017 1:58 am

Since Ba(OH)2 is a strong base, we know it completely disassociates. For every one mole of Ba(OH)2 that is diasassociated, there will be one mole of Ba+ and two moles of OH-. Therefore we multiply the base's concentration by two to get the concentration of OH-. From here we can calculate pOH


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