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12.29C

Posted: Thu Dec 07, 2017 12:33 am
by Connie2I
For problems such as 12.29C, why do we multiply Ba(OH)2 by 2 to get the concentration of OH? Is it because of the 2 outside the parentheses?

Re: 12.29C

Posted: Thu Dec 07, 2017 1:58 am
by AnuPanneerselvam1H
Since Ba(OH)2 is a strong base, we know it completely disassociates. For every one mole of Ba(OH)2 that is diasassociated, there will be one mole of Ba+ and two moles of OH-. Therefore we multiply the base's concentration by two to get the concentration of OH-. From here we can calculate pOH