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Vincent Chiang 1L
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Joined: Fri Sep 29, 2017 7:05 am


Postby Vincent Chiang 1L » Thu Dec 07, 2017 8:25 pm

Why does (x^2)/([Molarity of CH3COOH] - x) round to (x^2)/[Molarity of CH3COOH]?

Matthew Lee 3L
Posts: 51
Joined: Fri Sep 29, 2017 7:07 am

Re: 12.55(a)

Postby Matthew Lee 3L » Thu Dec 07, 2017 9:13 pm

Because CH3COOH is a weak acid, there is not much change in the concentration of CH3COOH. It does not dissociate very much. Thus, you can just ignore it and treat it as negligible.

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