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Postby MichelleTran3I » Thu Dec 07, 2017 11:53 pm

A careless laboratory technician wants to prepare 200.0 mL of a 0.025 M HCl(aq) solution, but uses a 250.0-mL volumetric ask by mistake. (a) What would the pH of the desired solution have been? (b) What will be the actual pH of the solution as prepared?

For part b, why do we continue to use the molarity of 0.025 M despite the new volume being in mL? Thanks!

Vincent Grospe 3C
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Joined: Fri Sep 29, 2017 7:07 am

Re: 12.27

Postby Vincent Grospe 3C » Fri Dec 08, 2017 12:47 pm

It is not being shown directly, but you will use the dilution equation M1V1 = M2V2 (you are solving for M2 in this case) in order to find the actual concentration of HCl, which will then give you the actual H30+ concentration.

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