12.33

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RenuChepuru1L
Posts: 58
Joined: Thu Jul 27, 2017 3:00 am

12.33

Postby RenuChepuru1L » Fri Dec 08, 2017 7:49 pm

can someone go through this problem step by step?

Jessica Jones 2B
Posts: 80
Joined: Fri Sep 29, 2017 7:04 am

Re: 12.33

Postby Jessica Jones 2B » Sat Dec 09, 2017 1:30 pm

First you will create the first reaction which is Na2O + H2O ----> 2NaOH, Then you go through the second reaction which is NaOH ----> NA+ + OH-. Based on this reaction you can find the concentration of [OH-] because the pH is 13.25 making pOH 0.75 and the concentration is 10^-.75, which gives you .18 mol. L-.
For the second part, you will need to use M1V1=M2V2. So, .18(500ml)= M(5ml), which equals 18 mol. L-.
Lastly, to find the mass you would take this concentrate and multiply it by 200x10^-3 L and then multiply by the molar ratio: 2 Na20 to 1 OH- and then multiply by the g.mol-1(61.98) which equals 110g.


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